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10x^2+9x-151=0
a = 10; b = 9; c = -151;
Δ = b2-4ac
Δ = 92-4·10·(-151)
Δ = 6121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{6121}}{2*10}=\frac{-9-\sqrt{6121}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{6121}}{2*10}=\frac{-9+\sqrt{6121}}{20} $
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